(-8v+1)*(-6v-7)=0

Solution for (-8v+1)*(-6v-7)=0 equation:

(-8v+1)(-6v-7)=0

We multiply parentheses ..

(+48v^2+56v-6v-7)=0

We get rid of parentheses

48v^2+56v-6v-7=0

We add all the numbers together, and all the variables

48v^2+50v-7=0

a = 48; b = 50; c = -7;
Δ = b2-4ac
Δ = 502-4·48·(-7)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*48}=\frac{-112}{96}
=-1+1/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*48}=\frac{12}{96}
=1/8
$