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(-8v+1)(-6v-7)=0
We multiply parentheses ..
(+48v^2+56v-6v-7)=0
We get rid of parentheses
48v^2+56v-6v-7=0
We add all the numbers together, and all the variables
48v^2+50v-7=0
a = 48; b = 50; c = -7;
Δ = b2-4ac
Δ = 502-4·48·(-7)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*48}=\frac{-112}{96} =-1+1/6 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*48}=\frac{12}{96} =1/8 $
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