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(-8x+4)(5x+3)=0
We multiply parentheses ..
(-40x^2-24x+20x+12)=0
We get rid of parentheses
-40x^2-24x+20x+12=0
We add all the numbers together, and all the variables
-40x^2-4x+12=0
a = -40; b = -4; c = +12;
Δ = b2-4ac
Δ = -42-4·(-40)·12
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*-40}=\frac{-40}{-80} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*-40}=\frac{48}{-80} =-3/5 $
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