(-8x+5)(-2-3x)=0

Solution for (-8x+5)(-2-3x)=0 equation:

(-8x+5)(-2-3x)=0

We add all the numbers together, and all the variables

(-8x+5)(-3x-2)=0

We multiply parentheses ..

(+24x^2+16x-15x-10)=0

We get rid of parentheses

24x^2+16x-15x-10=0

We add all the numbers together, and all the variables

24x^2+x-10=0

a = 24; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·24·(-10)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-31}{2*24}=\frac{-32}{48}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+31}{2*24}=\frac{30}{48}
=5/8
$