(-8x-3)/10=(-7x-2)/2

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Solution for (-8x-3)/10=(-7x-2)/2 equation: 



(-8x-3)/10=(-7x-2)/2

We move all terms to the left:

(-8x-3)/10-((-7x-2)/2)=0

We calculate fractions


(-8x)/()+(-((-7x-2)*10)/()=0



We calculate terms in parentheses: +(-((-7x-2)*10)/(), so:

-((-7x-2)*10)/(

We multiply all the terms by the denominator


-((-7x-2)*10)



We calculate terms in parentheses: -((-7x-2)*10), so:

(-7x-2)*10

We multiply parentheses

-70x-20

Back to the equation:

-(-70x-20)



We get rid of parentheses

70x+20

Back to the equation:

+(70x+20)



We get rid of parentheses

(-8x)/()+70x+20=0

We multiply all the terms by the denominator


(-8x)+70x*()+20*()=0

We add all the numbers together, and all the variables

(-8x)+70x*()=0

We get rid of parentheses

-8x+70x*()=0

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