(-8x-4)(-8x-6)=0

Solution for (-8x-4)(-8x-6)=0 equation:

(-8x-4)(-8x-6)=0

We multiply parentheses ..

(+64x^2+48x+32x+24)=0

We get rid of parentheses

64x^2+48x+32x+24=0

We add all the numbers together, and all the variables

64x^2+80x+24=0

a = 64; b = 80; c = +24;
Δ = b2-4ac
Δ = 802-4·64·24
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-16}{2*64}=\frac{-96}{128}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+16}{2*64}=\frac{-64}{128}
=-1/2
$