(-9)/(5y+29)=y/4

Solution for (-9)/(5y+29)=y/4 equation:

D( y )

5*y+29 = 0

5*y+29 = 0

5*y+29 = 0

5*y+29 = 0 // - 29

5*y = -29 // : 5

y = -29/5

y in (-oo:-29/5) U (-29/5:+oo)

-9/(5*y+29) = y/4 // - y/4

-9/(5*y+29)-(y/4) = 0

-9/(5*y+29)-y/4 = 0

(-9*4)/(4*(5*y+29))+(-y*(5*y+29))/(4*(5*y+29)) = 0

-y*(5*y+29)-9*4 = 0

-5*y^2-29*y-36 = 0

-5*y^2-29*y-36 = 0

-1*(5*y^2+29*y+36) = 0

5*y^2+29*y+36 = 0

DELTA = 29^2-(4*5*36)

DELTA = 121

DELTA > 0

y = (121^(1/2)-29)/(2*5) or y = (-121^(1/2)-29)/(2*5)

y = -9/5 or y = -4

-1*(y+4)*(y+9/5) = 0

(-1*(y+4)*(y+9/5))/(4*(5*y+29)) = 0

(-1*(y+4)*(y+9/5))/(4*(5*y+29)) = 0 // * 4*(5*y+29)

-1*(y+4)*(y+9/5) = 0

( y+4 )

y+4 = 0 // - 4

y = -4

( y+9/5 )

y+9/5 = 0 // - 9/5

y = -9/5

y in { -4, -9/5 }