(-9+-2x)(1+-3x)=0

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Solution for (-9+-2x)(1+-3x)=0 equation: 



(-9+-2x)(1+-3x)=0

We add all the numbers together, and all the variables

(-2x)(-3x)=0

We multiply parentheses ..

(+6x^2)=0

We get rid of parentheses

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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