(-9/2)(2b-2)+28=28

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Solution for (-9/2)(2b-2)+28=28 equation: 



(-9/2)(2b-2)+28=28

We move all terms to the left:

(-9/2)(2b-2)+28-(28)=0



Domain of the equation: 2)(2b-2)!=0

b∈R



We add all the numbers together, and all the variables

(-9/2)(2b-2)=0

We multiply parentheses ..

(-18b^2-9/2*-2)=0

We multiply all the terms by the denominator


(-18b^2-9=0

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