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(-X/2)(5-X)=360
We move all terms to the left:
(-X/2)(5-X)-(360)=0
Domain of the equation: 2)(5-X)!=0We add all the numbers together, and all the variables
X∈R
(-X/2)(-1X+5)-360=0
We multiply parentheses ..
(+X^2-5X)-360=0
We get rid of parentheses
X^2-5X-360=0
a = 1; b = -5; c = -360;
Δ = b2-4ac
Δ = -52-4·1·(-360)
Δ = 1465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1465}}{2*1}=\frac{5-\sqrt{1465}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1465}}{2*1}=\frac{5+\sqrt{1465}}{2} $
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