(-a+4b)/2a+(-5a-5b)/2a

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Solution for (-a+4b)/2a+(-5a-5b)/2a equation: 


x in (-oo:+oo)

a*((4*b-a)/2)+a*((-5*a-(5*b))/2) = 0

a*((4*b-a)/2)+a*((-5*a-5*b)/2) = 0

(a*(4*b-a))/2+(a*(-5*a-5*b))/2 = 0

a*(4*b-a)+a*(-5*a-5*b) = 0

-6*a^2-(a*b) = 0

(-6*a^2-(a*b))/2 = 0

(-6*a^2-(a*b))/2 = 0 // * 2

-6*a^2-(a*b) = 0

x belongs to the empty set

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