(-a-8)/10=(a+3)/2

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Solution for (-a-8)/10=(a+3)/2 equation: 



(-a-8)/10=(a+3)/2

We move all terms to the left:

(-a-8)/10-((a+3)/2)=0

We add all the numbers together, and all the variables

(-1a-8)/10-((a+3)/2)=0

We calculate fractions


(-a)/()+(-((a+3)*10)/()=0



We calculate terms in parentheses: +(-((a+3)*10)/(), so:

-((a+3)*10)/(

We multiply all the terms by the denominator


-((a+3)*10)



We calculate terms in parentheses: -((a+3)*10), so:

(a+3)*10

We multiply parentheses

10a+30

Back to the equation:

-(10a+30)



We get rid of parentheses

-10a-30

Back to the equation:

+(-10a-30)



We add all the numbers together, and all the variables

(-1a)/()+(-10a-30)=0

We get rid of parentheses

(-1a)/()-10a-30=0

We multiply all the terms by the denominator


(-1a)-10a*()-30*()=0

We add all the numbers together, and all the variables

(-1a)-10a*()=0

We get rid of parentheses

-1a-10a*()=0

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