(-c-11)(-c+1)=

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Solution for (-c-11)(-c+1)= equation:


Simplifying
(-1c + -11)(-1c + 1) = 0

Reorder the terms:
(-11 + -1c)(-1c + 1) = 0

Reorder the terms:
(-11 + -1c)(1 + -1c) = 0

Multiply (-11 + -1c) * (1 + -1c)
(-11(1 + -1c) + -1c * (1 + -1c)) = 0
((1 * -11 + -1c * -11) + -1c * (1 + -1c)) = 0
((-11 + 11c) + -1c * (1 + -1c)) = 0
(-11 + 11c + (1 * -1c + -1c * -1c)) = 0
(-11 + 11c + (-1c + 1c2)) = 0

Combine like terms: 11c + -1c = 10c
(-11 + 10c + 1c2) = 0

Solving
-11 + 10c + 1c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-11 + -1c)(1 + -1c) = 0

Subproblem 1

Set the factor '(-11 + -1c)' equal to zero and attempt to solve: Simplifying -11 + -1c = 0 Solving -11 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + -1c = 0 + 11 Combine like terms: -11 + 11 = 0 0 + -1c = 0 + 11 -1c = 0 + 11 Combine like terms: 0 + 11 = 11 -1c = 11 Divide each side by '-1'. c = -11 Simplifying c = -11

Subproblem 2

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Solution

c = {-11, 1}

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