(-j/12)=-8

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Solution for (-j/12)=-8 equation: 


0.029-(2.5*x)+0.03 = 0;x

x

5*x^3-x^4-6*x^2;x-2

5*x^3-x^4-6*x^2;2

6*9-(-3*(7/2))

(3*x^2-(2*x^(1/2)))*(2*x^4-(3*(x^4)^(1/3)))

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