(-x)+4x+(-2)=3(-x)+(-10)

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Solution for (-x)+4x+(-2)=3(-x)+(-10) equation: 



(-x)+4x+(-2)=3(-x)+(-10)

We move all terms to the left:

(-x)+4x+(-2)-(3(-x)+(-10))=0

We add all the numbers together, and all the variables

(-1x)+4x-(3(-1x)+(-10))+(-2)=0

We add all the numbers together, and all the variables

4x+(-1x)-(3(-1x)+(-10))-2=0

We get rid of parentheses

4x-1x-(3(-1x)+(-10))-2=0



We calculate terms in parentheses: -(3(-1x)+(-10)), so:

3(-1x)+(-10)

We add all the numbers together, and all the variables

3(-1x)-10

We multiply parentheses

-3x-10

Back to the equation:

-(-3x-10)



We add all the numbers together, and all the variables

3x-(-3x-10)-2=0

We get rid of parentheses

3x+3x+10-2=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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