(-x+3)(6x-2)=0

Solution for (-x+3)(6x-2)=0 equation:

(-x+3)(6x-2)=0

We add all the numbers together, and all the variables

(-1x+3)(6x-2)=0

We multiply parentheses ..

(-6x^2+2x+18x-6)=0

We get rid of parentheses

-6x^2+2x+18x-6=0

We add all the numbers together, and all the variables

-6x^2+20x-6=0

a = -6; b = 20; c = -6;
Δ = b2-4ac
Δ = 202-4·(-6)·(-6)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-16}{2*-6}=\frac{-36}{-12}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+16}{2*-6}=\frac{-4}{-12}
=1/3
$