(-x+3)(8x-8)=0

Solution for (-x+3)(8x-8)=0 equation:

(-x+3)(8x-8)=0

We add all the numbers together, and all the variables

(-1x+3)(8x-8)=0

We multiply parentheses ..

(-8x^2+8x+24x-24)=0

We get rid of parentheses

-8x^2+8x+24x-24=0

We add all the numbers together, and all the variables

-8x^2+32x-24=0

a = -8; b = 32; c = -24;
Δ = b2-4ac
Δ = 322-4·(-8)·(-24)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16}{2*-8}=\frac{-48}{-16}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16}{2*-8}=\frac{-16}{-16}
=1
$