(-x+3)-(7-4x)=5x+2X(x+1)

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Solution for (-x+3)-(7-4x)=5x+2X(x+1) equation: 



(-x+3)-(7-4x)=5x+2x(x+1)

We move all terms to the left:

(-x+3)-(7-4x)-(5x+2x(x+1))=0

We add all the numbers together, and all the variables

(-1x+3)-(-4x+7)-(5x+2x(x+1))=0

We get rid of parentheses

-1x+4x-(5x+2x(x+1))+3-7=0



We calculate terms in parentheses: -(5x+2x(x+1)), so:

5x+2x(x+1)

We multiply parentheses

2x^2+5x+2x

We add all the numbers together, and all the variables

2x^2+7x

Back to the equation:

-(2x^2+7x)



We add all the numbers together, and all the variables

3x-(2x^2+7x)-4=0

We get rid of parentheses

-2x^2+3x-7x-4=0

We add all the numbers together, and all the variables

-2x^2-4x-4=0

a = -2; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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