(-x+5)(x+2)=18

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Solution for (-x+5)(x+2)=18 equation: 



(-x+5)(x+2)=18

We move all terms to the left:

(-x+5)(x+2)-(18)=0

We add all the numbers together, and all the variables

(-1x+5)(x+2)-18=0

We multiply parentheses ..

(-1x^2-2x+5x+10)-18=0

We get rid of parentheses

-1x^2-2x+5x+10-18=0

We add all the numbers together, and all the variables

-1x^2+3x-8=0

a = -1; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·(-1)·(-8)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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