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(-x+5)(x+2)=18
We move all terms to the left:
(-x+5)(x+2)-(18)=0
We add all the numbers together, and all the variables
(-1x+5)(x+2)-18=0
We multiply parentheses ..
(-1x^2-2x+5x+10)-18=0
We get rid of parentheses
-1x^2-2x+5x+10-18=0
We add all the numbers together, and all the variables
-1x^2+3x-8=0
a = -1; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·(-1)·(-8)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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