(-x+6)(-5x-8)=0

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Solution for (-x+6)(-5x-8)=0 equation:



(-x+6)(-5x-8)=0
We add all the numbers together, and all the variables
(-1x+6)(-5x-8)=0
We multiply parentheses ..
(+5x^2+8x-30x-48)=0
We get rid of parentheses
5x^2+8x-30x-48=0
We add all the numbers together, and all the variables
5x^2-22x-48=0
a = 5; b = -22; c = -48;
Δ = b2-4ac
Δ = -222-4·5·(-48)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-38}{2*5}=\frac{-16}{10} =-1+3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+38}{2*5}=\frac{60}{10} =6 $

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