(-x-)(2x-3)=4

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Solution for (-x-)(2x-3)=4 equation: 



(-x-)(2x-3)=4

We move all terms to the left:

(-x-)(2x-3)-(4)=0

We add all the numbers together, and all the variables

(-1x)(2x-3)-4=0

We multiply parentheses ..

(-2x^2+3x)-4=0

We get rid of parentheses

-2x^2+3x-4=0

a = -2; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-2)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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