(-x-4)-(4x-2+3)=-(6x-8)+(2x-4+3)

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Solution for (-x-4)-(4x-2+3)=-(6x-8)+(2x-4+3) equation: 



(-x-4)-(4x-2+3)=-(6x-8)+(2x-4+3)

We move all terms to the left:

(-x-4)-(4x-2+3)-(-(6x-8)+(2x-4+3))=0

We add all the numbers together, and all the variables

(-1x-4)-(4x+1)-(-(6x-8)+(2x-1))=0

We get rid of parentheses

-1x-4x-(-(6x-8)+(2x-1))-4-1=0



We calculate terms in parentheses: -(-(6x-8)+(2x-1)), so:

-(6x-8)+(2x-1)

We get rid of parentheses

-6x+2x+8-1

We add all the numbers together, and all the variables

-4x+7

Back to the equation:

-(-4x+7)



We add all the numbers together, and all the variables

-5x-(-4x+7)-5=0

We get rid of parentheses

-5x+4x-7-5=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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