(-x2-2x)=(x2-4x-3)

Solution for (-x2-2x)=(x2-4x-3) equation:

(-x2-2x)=(x2-4x-3)

We move all terms to the left:

(-x2-2x)-((x2-4x-3))=0

We add all the numbers together, and all the variables

(-1x^2-2x)-((+x^2-4x-3))=0

We get rid of parentheses

-1x^2-((+x^2-4x-3))-2x=0


We calculate terms in parentheses: -((+x^2-4x-3)), so:

(+x^2-4x-3)

We get rid of parentheses

x^2-4x-3

Back to the equation:

-(x^2-4x-3)


We add all the numbers together, and all the variables

-1x^2-2x-(x^2-4x-3)=0

We get rid of parentheses

-1x^2-x^2-2x+4x+3=0

We add all the numbers together, and all the variables

-2x^2+2x+3=0

a = -2; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·(-2)·3
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{7}}{2*-2}=\frac{-2-2\sqrt{7}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{7}}{2*-2}=\frac{-2+2\sqrt{7}}{-4}
$