(-z+37)+(7z-85)=2(4z-41)

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Solution for (-z+37)+(7z-85)=2(4z-41) equation: 



(-z+37)+(7z-85)=2(4z-41)

We move all terms to the left:

(-z+37)+(7z-85)-(2(4z-41))=0

We add all the numbers together, and all the variables

(-1z+37)+(7z-85)-(2(4z-41))=0

We get rid of parentheses

-1z+7z-(2(4z-41))+37-85=0



We calculate terms in parentheses: -(2(4z-41)), so:

2(4z-41)

We multiply parentheses

8z-82

Back to the equation:

-(8z-82)



We add all the numbers together, and all the variables

6z-(8z-82)-48=0

We get rid of parentheses

6z-8z+82-48=0

We add all the numbers together, and all the variables

-2z+34=0

We move all terms containing z to the left, all other terms to the right

-2z=-34

z=-34/-2

z=+17

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