(.1x-22)+(.3x-54)=90

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Solution for (.1x-22)+(.3x-54)=90 equation: 



(.1x-22)+(.3x-54)=90

We move all terms to the left:

(.1x-22)+(.3x-54)-(90)=0

We get rid of parentheses

.1x+.3x-22-54-90=0

We add all the numbers together, and all the variables

0.4x-166=0

We move all terms containing x to the left, all other terms to the right

0.4x=166

x=166/0.4

x=415

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