(.1x-22)+(.3x-54)=90

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Solution for (.1x-22)+(.3x-54)=90 equation:



(.1x-22)+(.3x-54)=90
We move all terms to the left:
(.1x-22)+(.3x-54)-(90)=0
We get rid of parentheses
.1x+.3x-22-54-90=0
We add all the numbers together, and all the variables
0.4x-166=0
We move all terms containing x to the left, all other terms to the right
0.4x=166
x=166/0.4
x=415

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