(0+4-1+x+5+3)/6=2

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Solution for (0+4-1+x+5+3)/6=2 equation: 



(0+4-1+x+5+3)/6=2

We move all terms to the left:

(0+4-1+x+5+3)/6-(2)=0

We add all the numbers together, and all the variables

(x+11)/6-2=0

We multiply all the terms by the denominator


(x+11)-2*6=0

We add all the numbers together, and all the variables

(x+11)-12=0

We get rid of parentheses

x+11-12=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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