(0,1-x)(0,1-x)=0

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Solution for (0,1-x)(0,1-x)=0 equation:



(0.1-x)(0.1-x)=0
We add all the numbers together, and all the variables
(-1x+0.1)(-1x+0.1)=0
We multiply parentheses ..
(+x^2-0.1x-0.1x+0.01)=0
We get rid of parentheses
x^2-0.1x-0.1x+0.01=0
We add all the numbers together, and all the variables
x^2-0.2x+0.01=0
a = 1; b = -0.2; c = +0.01;
Δ = b2-4ac
Δ = -0.22-4·1·0.01
Δ = 6.9388939039072E-18
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{6.9388939039072E-18}}{2*1}=\frac{0.2-\sqrt{6.9388939039072E-18}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{6.9388939039072E-18}}{2*1}=\frac{0.2+\sqrt{6.9388939039072E-18}}{2} $

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