(0,1-z)z=0

Solution for (0,1-z)z=0 equation:

(0.1-z)z=0

We add all the numbers together, and all the variables

(-1z+0.1)z=0

We multiply parentheses

-1z^2+0.1z=0

a = -1; b = 0.1; c = 0;
Δ = b2-4ac
Δ = 0.12-4·(-1)·0
Δ = 0.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1)-\sqrt{0.01}}{2*-1}=\frac{-0.1-\sqrt{0.01}}{-2}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1)+\sqrt{0.01}}{2*-1}=\frac{-0.1+\sqrt{0.01}}{-2}
$