(0,8-x)(1-x)=0

Solution for (0,8-x)(1-x)=0 equation:

(0.8-x)(1-x)=0

We add all the numbers together, and all the variables

(-1x+0.8)(-1x+1)=0

We multiply parentheses ..

(+x^2-1x-0.8x+0.8)=0

We get rid of parentheses

x^2-1x-0.8x+0.8=0

We add all the numbers together, and all the variables

x^2-1.8x+0.8=0

a = 1; b = -1.8; c = +0.8;
Δ = b2-4ac
Δ = -1.82-4·1·0.8
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.8)-\sqrt{0.04}}{2*1}=\frac{1.8-\sqrt{0.04}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.8)+\sqrt{0.04}}{2*1}=\frac{1.8+\sqrt{0.04}}{2}
$