(0,8x-2)(3x+1)=0

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Solution for (0,8x-2)(3x+1)=0 equation:



(0.8x-2)(3x+1)=0
We multiply parentheses ..
(+0x^2+0x-6x-2)=0
We get rid of parentheses
0x^2+0x-6x-2=0
We add all the numbers together, and all the variables
x^2-5x-2=0
a = 1; b = -5; c = -2;
Δ = b2-4ac
Δ = -52-4·1·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{33}}{2*1}=\frac{5-\sqrt{33}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{33}}{2*1}=\frac{5+\sqrt{33}}{2} $

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