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(0.02-x)(0.01-x)=0
We add all the numbers together, and all the variables
(-1x+0.02)(-1x+0.01)=0
We multiply parentheses ..
(+x^2-0.01x-0.02x+0.0002)=0
We get rid of parentheses
x^2-0.01x-0.02x+0.0002=0
We add all the numbers together, and all the variables
x^2-0.03x+0.0002=0
a = 1; b = -0.03; c = +0.0002;
Δ = b2-4ac
Δ = -0.032-4·1·0.0002
Δ = 0.0001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.03)-\sqrt{0.0001}}{2*1}=\frac{0.03-\sqrt{0.0001}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.03)+\sqrt{0.0001}}{2*1}=\frac{0.03+\sqrt{0.0001}}{2} $
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