(0.05-x)(0.1-x)=0

Solution for (0.05-x)(0.1-x)=0 equation:

(0.05-x)(0.1-x)=0

We add all the numbers together, and all the variables

(-1x+0.05)(-1x+0.1)=0

We multiply parentheses ..

(+x^2-0.1x-0.05x+0.005)=0

We get rid of parentheses

x^2-0.1x-0.05x+0.005=0

We add all the numbers together, and all the variables

x^2-0.15x+0.005=0

a = 1; b = -0.15; c = +0.005;
Δ = b2-4ac
Δ = -0.152-4·1·0.005
Δ = 0.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.15)-\sqrt{0.0025}}{2*1}=\frac{0.15-\sqrt{0.0025}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.15)+\sqrt{0.0025}}{2*1}=\frac{0.15+\sqrt{0.0025}}{2}
$