(0.050+x)(0.040+x)=0

Solution for (0.050+x)(0.040+x)=0 equation:

(0.050+x)(0.040+x)=0

We add all the numbers together, and all the variables

(x+0.05)(x+0.04)=0

We multiply parentheses ..

(+x^2+0.04x+0.05x+0.002)=0

We get rid of parentheses

x^2+0.04x+0.05x+0.002=0

We add all the numbers together, and all the variables

x^2+0.09x+0.002=0

a = 1; b = 0.09; c = +0.002;
Δ = b2-4ac
Δ = 0.092-4·1·0.002
Δ = 0.0001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.09)-\sqrt{0.0001}}{2*1}=\frac{-0.09-\sqrt{0.0001}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.09)+\sqrt{0.0001}}{2*1}=\frac{-0.09+\sqrt{0.0001}}{2}
$