(0.12-x)(0.12-x)=0

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Solution for (0.12-x)(0.12-x)=0 equation: 



(0.12-x)(0.12-x)=0

We add all the numbers together, and all the variables

(-1x+0.12)(-1x+0.12)=0

We multiply parentheses ..

(+x^2-0.12x-0.12x+0.0144)=0

We get rid of parentheses

x^2-0.12x-0.12x+0.0144=0

We add all the numbers together, and all the variables

x^2-0.24x+0.0144=0

a = 1; b = -0.24; c = +0.0144;
Δ = b2-4ac
Δ = -0.242-4·1·0.0144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0.24}{2}=0.24/2$

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