(0.20-x)(0.19-x)=0

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Solution for (0.20-x)(0.19-x)=0 equation:



(0.20-x)(0.19-x)=0
We add all the numbers together, and all the variables
(-1x+0.2)(-1x+0.19)=0
We multiply parentheses ..
(+x^2-0.19x-0.2x+0.038)=0
We get rid of parentheses
x^2-0.19x-0.2x+0.038=0
We add all the numbers together, and all the variables
x^2-0.39x+0.038=0
a = 1; b = -0.39; c = +0.038;
Δ = b2-4ac
Δ = -0.392-4·1·0.038
Δ = 0.00010000000000002
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.39)-\sqrt{0.00010000000000002}}{2*1}=\frac{0.39-\sqrt{0.00010000000000002}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.39)+\sqrt{0.00010000000000002}}{2*1}=\frac{0.39+\sqrt{0.00010000000000002}}{2} $

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