(0.3-x)(1.3-x)-(0.6)(-0.35)=0

Solution for (0.3-x)(1.3-x)-(0.6)(-0.35)=0 equation:

(0.3-x)(1.3-x)-(0.6)(-0.35)=0

We add all the numbers together, and all the variables

(-1x+0.3)(-1x+1.3)-(0.6)(-0.35)=0

We add all the numbers together, and all the variables

(-1x+0.3)(-1x+1.3)+0.21=0

We multiply parentheses ..

(+x^2-1.3x-0.3x+0.39)+0.21=0

We get rid of parentheses

x^2-1.3x-0.3x+0.39+0.21=0

We add all the numbers together, and all the variables

x^2-1.6x+0.6=0

a = 1; b = -1.6; c = +0.6;
Δ = b2-4ac
Δ = -1.62-4·1·0.6
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{0.16}}{2*1}=\frac{1.6-\sqrt{0.16}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{0.16}}{2*1}=\frac{1.6+\sqrt{0.16}}{2}
$