(0.3x)(0.4x)=6.32

Solution for (0.3x)(0.4x)=6.32 equation:

(0.3x)(0.4x)=6.32

We move all terms to the left:

(0.3x)(0.4x)-(6.32)=0

We add all the numbers together, and all the variables

(+0.3x)(+0.4x)-(6.32)=0

We add all the numbers together, and all the variables

(+0.3x)(+0.4x)-6.32=0

We multiply parentheses ..

(+0x^2)-6.32=0

We get rid of parentheses

0x^2-6.32=0

We add all the numbers together, and all the variables

x^2-6.32=0

a = 1; b = 0; c = -6.32;
Δ = b2-4ac
Δ = 02-4·1·(-6.32)
Δ = 25.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.28}}{2*1}=\frac{0-\sqrt{25.28}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.28}}{2*1}=\frac{0+\sqrt{25.28}}{2}
=\frac{\sqrt{}}{2}
$