(0.3x)+(x)+(x+20)=132

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Solution for (0.3x)+(x)+(x+20)=132 equation: 



(0.3x)+(x)+(x+20)=132

We move all terms to the left:

(0.3x)+(x)+(x+20)-(132)=0

We add all the numbers together, and all the variables

(+0.3x)+x+(x+20)-132=0

We add all the numbers together, and all the variables

x+(+0.3x)+(x+20)-132=0

We get rid of parentheses

x+0.3x+x+20-132=0

We add all the numbers together, and all the variables

2.3x-112=0

We move all terms containing x to the left, all other terms to the right

2.3x=112

x=112/2.3

x=48+1/1.4375

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