(0.4-x)*(1.2-x)=0

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Solution for (0.4-x)*(1.2-x)=0 equation:



(0.4-x)(1.2-x)=0
We add all the numbers together, and all the variables
(-1x+0.4)(-1x+1.2)=0
We multiply parentheses ..
(+x^2-1.2x-0.4x+0.48)=0
We get rid of parentheses
x^2-1.2x-0.4x+0.48=0
We add all the numbers together, and all the variables
x^2-1.6x+0.48=0
a = 1; b = -1.6; c = +0.48;
Δ = b2-4ac
Δ = -1.62-4·1·0.48
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{0.64}}{2*1}=\frac{1.6-\sqrt{0.64}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{0.64}}{2*1}=\frac{1.6+\sqrt{0.64}}{2} $

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