(0.5)(x+1)*4(2x)=0.25

Solution for (0.5)(x+1)*4(2x)=0.25 equation:

(0.5)(x+1)*4(2x)=0.25

We move all terms to the left:

(0.5)(x+1)*4(2x)-(0.25)=0

We add all the numbers together, and all the variables

(0.5)(x+1)*42x-0.25=0

We multiply parentheses ..

(+0.5x+0.5)*42x-0.25=0

We add all the numbers together, and all the variables

(0.5x+0.5)*42x-0.25=0

We multiply parentheses

0x^2+21x-0.25=0

We add all the numbers together, and all the variables

x^2+21x-0.25=0

a = 1; b = 21; c = -0.25;
Δ = b2-4ac
Δ = 212-4·1·(-0.25)
Δ = 442
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{442}}{2*1}=\frac{-21-\sqrt{442}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{442}}{2*1}=\frac{-21+\sqrt{442}}{2}
$