(0.6)(3x)+(0.2)(x)=1400

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Solution for (0.6)(3x)+(0.2)(x)=1400 equation: 



(0.6)(3x)+(0.2)(x)=1400

We move all terms to the left:

(0.6)(3x)+(0.2)(x)-(1400)=0

We multiply parentheses

1.8x+0.2x-1400=0

We add all the numbers together, and all the variables

2x-1400=0

We move all terms containing x to the left, all other terms to the right

2x=1400

x=1400/2

x=700

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