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(0.6-x)(1.18-x)=3.0(0.8+x)(0.1+x)
We move all terms to the left:
(0.6-x)(1.18-x)-(3.0(0.8+x)(0.1+x))=0
We add all the numbers together, and all the variables
(-1x+0.6)(-1x+1.18)-(3.0(x+0.8)(x+0.1))=0
We multiply parentheses ..
(+x^2-1.18x-0.6x+0.708)-(3.0(x+0.8)(x+0.1))=0
We calculate terms in parentheses: -(3.0(x+0.8)(x+0.1)), so:We get rid of parentheses
3.0(x+0.8)(x+0.1)
We multiply parentheses ..
3.0(+x^2+0.1x+0.8x+0.08)
We multiply parentheses
3x^2+0x+0x+0.24
We add all the numbers together, and all the variables
3x^2+2x+0.24
Back to the equation:
-(3x^2+2x+0.24)
x^2-3x^2-1.18x-0.6x-2x+0.708-0.24=0
We add all the numbers together, and all the variables
-2x^2-3.78x+0.468=0
a = -2; b = -3.78; c = +0.468;
Δ = b2-4ac
Δ = -3.782-4·(-2)·0.468
Δ = 18.0324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.78)-\sqrt{18.0324}}{2*-2}=\frac{3.78-\sqrt{18.0324}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.78)+\sqrt{18.0324}}{2*-2}=\frac{3.78+\sqrt{18.0324}}{-4} $
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