(0.8-x)(0.4-x)=0

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Solution for (0.8-x)(0.4-x)=0 equation:



(0.8-x)(0.4-x)=0
We add all the numbers together, and all the variables
(-1x+0.8)(-1x+0.4)=0
We multiply parentheses ..
(+x^2-0.4x-0.8x+0.32)=0
We get rid of parentheses
x^2-0.4x-0.8x+0.32=0
We add all the numbers together, and all the variables
x^2-1.2x+0.32=0
a = 1; b = -1.2; c = +0.32;
Δ = b2-4ac
Δ = -1.22-4·1·0.32
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{0.16}}{2*1}=\frac{1.2-\sqrt{0.16}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{0.16}}{2*1}=\frac{1.2+\sqrt{0.16}}{2} $

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