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(0.8-x)(0.5-x)=0
We add all the numbers together, and all the variables
(-1x+0.8)(-1x+0.5)=0
We multiply parentheses ..
(+x^2-0.5x-0.8x+0.4)=0
We get rid of parentheses
x^2-0.5x-0.8x+0.4=0
We add all the numbers together, and all the variables
x^2-1.3x+0.4=0
a = 1; b = -1.3; c = +0.4;
Δ = b2-4ac
Δ = -1.32-4·1·0.4
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.3)-\sqrt{0.09}}{2*1}=\frac{1.3-\sqrt{0.09}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.3)+\sqrt{0.09}}{2*1}=\frac{1.3+\sqrt{0.09}}{2} $
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