(1)(3)=(c+5)(2)

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Solution for (1)(3)=(c+5)(2) equation: 



(1)(3)=(c+5)(2)

We move all terms to the left:

(1)(3)-((c+5)(2))=0



We calculate terms in parentheses: -((c+5)2), so:

(c+5)2

We multiply parentheses

2c+10

Back to the equation:

-(2c+10)



We get rid of parentheses

-2c-10+13=0

We add all the numbers together, and all the variables

-2c+3=0

We move all terms containing c to the left, all other terms to the right

-2c=-3

c=-3/-2

c=1+1/2

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