(1)(b-3)+(1)(b+3)=(2)(4)

Solution for (1)(b-3)+(1)(b+3)=(2)(4) equation:

Simplifying
(1)(b + -3) + (1)(b + 3) = (2)(4)

Reorder the terms:
1(-3 + b) + (1)(b + 3) = (2)(4)
(-3 * 1 + b * 1) + (1)(b + 3) = (2)(4)
(-3 + 1b) + (1)(b + 3) = (2)(4)

Reorder the terms:
-3 + 1b + 1(3 + b) = (2)(4)
-3 + 1b + (3 * 1 + b * 1) = (2)(4)
-3 + 1b + (3 + 1b) = (2)(4)

Reorder the terms:
-3 + 3 + 1b + 1b = (2)(4)

Combine like terms: -3 + 3 = 0
0 + 1b + 1b = (2)(4)
1b + 1b = (2)(4)

Combine like terms: 1b + 1b = 2b
2b = (2)(4)

Multiply 2 * 4
2b = 8

Solving
2b = 8

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '2'.
b = 4

Simplifying
b = 4