(1)/(10)(x+50)=-3x-13+4x

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Solution for (1)/(10)(x+50)=-3x-13+4x equation: 



(1)/(10)(x+50)=-3x-13+4x

We move all terms to the left:

(1)/(10)(x+50)-(-3x-13+4x)=0



Domain of the equation: 10(x+50)!=0

x∈R



We add all the numbers together, and all the variables

1/10(x+50)-(x-13)=0

We get rid of parentheses

1/10(x+50)-x+13=0

We multiply all the terms by the denominator


-x*10(x+50)+13*10(x+50)+1=0

Wy multiply elements

-10x^2(x+130x(x+1=0

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