(1)/(2)(4z+8)-16=-(2)/(3)(9z-12)

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Solution for (1)/(2)(4z+8)-16=-(2)/(3)(9z-12) equation: 



(1)/(2)(4z+8)-16=-(2)/(3)(9z-12)

We move all terms to the left:

(1)/(2)(4z+8)-16-(-(2)/(3)(9z-12))=0



Domain of the equation: 2(4z+8)!=0

z∈R





Domain of the equation: 3(9z-12))!=0

z∈R



We calculate fractions


(3z9/(2(4z+8)*3(9z-12)))+(-(-4z4)/(2(4z+8)*3(9z-12)))-16=0



We calculate terms in parentheses: +(3z9/(2(4z+8)*3(9z-12))), so:

3z9/(2(4z+8)*3(9z-12))

We multiply all the terms by the denominator


3z9

We add all the numbers together, and all the variables

3z^9

We do not support ezpression: z^9

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