(1)/(2)(n-4)-7=-2n+6

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Solution for (1)/(2)(n-4)-7=-2n+6 equation: 



(1)/(2)(n-4)-7=-2n+6

We move all terms to the left:

(1)/(2)(n-4)-7-(-2n+6)=0



Domain of the equation: 2(n-4)!=0

n∈R



We get rid of parentheses

1/2(n-4)+2n-6-7=0

We multiply all the terms by the denominator


2n*2(n-4)-6*2(n-4)-7*2(n-4)+1=0

Wy multiply elements

4n^2(n-12n(n-14n(n+1=0

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