(1)/(2)(x-3)+x=17+3(4-x)

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Solution for (1)/(2)(x-3)+x=17+3(4-x) equation: 



(1)/(2)(x-3)+x=17+3(4-x)

We move all terms to the left:

(1)/(2)(x-3)+x-(17+3(4-x))=0



Domain of the equation: 2(x-3)!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-3)+x-(17+3(-1x+4))=0

We add all the numbers together, and all the variables

x+1/2(x-3)-(17+3(-1x+4))=0

We multiply all the terms by the denominator


x*2(x-3)-((17+3(-1x+4)))*2(x-3)+1=0



We calculate terms in parentheses: -((17+3(-1x+4)))*2(x-3), so:

(17+3(-1x+4)))*2(x-3



Wy multiply elements

2x^2(x-((17+3(-1x+4)))*2(x-3)+1=0

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