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(1)/(2)(x-4)-(5+x)=x
We move all terms to the left:
(1)/(2)(x-4)-(5+x)-(x)=0
Domain of the equation: 2(x-4)!=0We add all the numbers together, and all the variables
x∈R
1/2(x-4)-(x+5)-x=0
We add all the numbers together, and all the variables
-1x+1/2(x-4)-(x+5)=0
We get rid of parentheses
-1x+1/2(x-4)-x-5=0
We multiply all the terms by the denominator
-1x*2(x-4)-x*2(x-4)-5*2(x-4)+1=0
Wy multiply elements
-2x^2(x-2x^2(x-10x(x+1=0
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